Loops and Collatz

+ <stdio.h>
f main()
  total:=0
  for i := 1; i < 11; i++
    total += i
  printf("sum 1..10 = %d\n", total)
  n:=27
  steps:=0
  while n != 1
    n = n % 2 ? 3 * n + 1 : n / 2
    ++steps
  printf("collatz(27) takes %d steps\n", steps)
  < 0

#include <stdio.h>

int main(void) {
    int total = 0;
    for (int i = 1; i < 11; i++) {
        total += i;
    }
    printf("sum 1..10 = %d\n", total);
    int n = 27;
    int steps = 0;
    while (n != 1) {
        n = n % 2 ? 3 * n + 1 : n / 2;
        ++steps;
    }
    printf("collatz(27) takes %d steps\n", steps);
    return 0;
}